Question

Solve the linear equation by substitution method
7x + 11y-3=0
8x + y-15=0

Answer 1

I think it's your answer.

Answer 2

Ahoy user!

The answer:-

7x+11y = 3. .........(i)
8x+y = 15. ........(ii)

From, eq(ii) we can write ,
y= 15-8x


Now, Putting the value of y in eq (i) we get,
7x + 11(15-8x) = 3

= 7x + 165 -88x = 3

= -81x = 3-165

=> -81x = -162

=> x = -162÷-81

=> x = 2

Putting the value of x in the substitution of y we get,

y=15-8x

y = 15 -8×2

= 15-16

y=> -1



hope this helps!
Good day!