Question

solve the linear equation for 'x'

Answer 1

I solved yours answer and Mark me As a brainlist

Answer 2

Hey Mate,

Given Equation,

=> $\frac{2x-3}{5}+\frac{x+3}{4}=\frac{2x+3}{4}$

Then, On taking the LCM of 4 and 5 as 20 we get :-

=> $\frac{4(2x-3)}{20}+\frac{5(x+3)}{20}=\frac{5(2x+3)}{20}$

=> $\frac{8x-12+5x+15}{20}=\frac{10x+15}{20}$

Now, On cross - multiplying we get :-

=> $20(8x-12+5x+15)=20(10x+15)$

Since, 20 is common in both LHS and RHS, we can cancel both the 20's :-

=> $8x-12+5x+15=10x+15$

=> $13x+3=10x+15$

=> $3x=12$

=> $<strong>x = 4</strong>$

Therefore, x = 4 is the solution for :-

$\frac{2x-3}{5}+\frac{x+3}{4}=\frac{2x+3}{4}$

Hope My Answer Brings A Smile On Your Face !

^_^