Math, asked by taranpk06, 10 months ago

Solve the linear equation graphically 3x-5y+1=0 and 2x-y+3=0

Answers

Answered by Anonymous
1

Answer:

Please give me a graph dear friend

Step-by-step explanation:

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Answered by SweetPoison7
6

\huge\blue{\mid{\fbox{\tt{Answer}}\mid}}

\tt\large\green\rightarrow3x-5y+1=0 ---------(1)

\tt\large\green\rightarrow2x-y+3=0 ----------(2)

multiplying eqn (2) by 5 we get

\tt\large\green\rightarrow10x-5y+15=0 ---------(3)

subtracting eqn (3) from eqn (1) , we get

\tt\large\green\rightarrow(3x-5y+1) - (10x-5y+15) =0-0

\tt\large\green\rightarrow3x-5y+1-10x+5y-15=0

\tt\large\green\rightarrow-7x-14=0

\tt\large\green\rightarrow-7x=14

\tt\large\green\rightarrowx = -2

putting the value of x = -2 in eqn (2) we get

\tt\large\green\rightarrow2 (-2)-y+3=0

\tt\large\green\rightarrow-4-y+3 =0

\tt\large\green\rightarrow-y-1=0

\tt\large\green\rightarrow-y=1

\tt\large\green\rightarrowy = -1

x = -2 and y = -1

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