Math, asked by thekhan0999, 2 months ago

Solve the linear equation in two variables: x+3y=6 and 2x-3y=12​

Answers

Answered by chinmayibv668
0

Answer:

x=6 ,y=0

Step-by-step explanation:

Subtracting both equations

   2x-3y=12

   - x+3y=6

       x+0=6

Therefore x=6

substituting x

2(6)-3y=12

12-3y=12

   -3y=12-12=0

      y=0/-3=0

Therefore y=0

Answered by angitaaaaaaaaaaaaaa
0

Answer:

X = 3 and y= 0

Step-by-step explanation:

x+3y = 6

x=6-3y------1

2x-3y=12

=> 2(6-3y)-3y =12 ( from equation 1)

=>12 - 6y-3y =12

=> - 9y = 12-12

=> - 9y =0

=> y =0

Now

x + 3y = 6

=>x + 3×0=6

=> x +3= 6

=>x = 6-3

= 3

x = 3 and y = 0

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