Solve the linear equation in two variables: x+3y=6 and 2x-3y=12
Answers
Answered by
0
Answer:
x=6 ,y=0
Step-by-step explanation:
Subtracting both equations
2x-3y=12
- x+3y=6
x+0=6
Therefore x=6
substituting x
2(6)-3y=12
12-3y=12
-3y=12-12=0
y=0/-3=0
Therefore y=0
Answered by
0
Answer:
X = 3 and y= 0
Step-by-step explanation:
x+3y = 6
x=6-3y------1
2x-3y=12
=> 2(6-3y)-3y =12 ( from equation 1)
=>12 - 6y-3y =12
=> - 9y = 12-12
=> - 9y =0
=> y =0
Now
x + 3y = 6
=>x + 3×0=6
=> x +3= 6
=>x = 6-3
= 3
x = 3 and y = 0
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