Question

solve the linear equation with steps​

Answer 1

$\sf {\frac{1}{x+1} = \frac{3}{4(x-1)}}$

→ $\sf{4(x-1) = 3(x+1)}$

→ $\sf{4x -4=3x+3}$

→ $\sf{4x-3x=3+4}$

→ $\boxed{\red{\sf{x=7}}}$