Question

Solve the linear equations:
a) 8(x - 5) = 200
b) 15y + 23 = 12y - 1

Answer 1

Answer:

1] 8 ( x - 5 ) = 200

$\longrightarrow\sf{ 8x - 40 = 200 }$

$\longrightarrow\sf{ 8x = 200 + 40 }$

$\longrightarrow\sf{ 8x = 240 }$

$\longrightarrow\sf{ x = \dfrac{240}{8} }$

$\longrightarrow\sf{ x = 30 }$

2] 15y + 22 = 12y - 1

$\longrightarrow\sf{ 15y - 12y = -1 - 22 }$

$\longrightarrow\sf{ 3y = - 23 }$

$\longrightarrow\sf{ y = \dfrac{-23}{3}}$

Answer 2

1. 8(x-5) = 200
Pehle multiply krde
8x-40 = 200
40 udhar jake + hojayega
8x = 200+40
8x= 240
X = 240/8
X= 30

2.15y+23 = 12y-1
Sari y terms ko ek taraf le aa
15y-12y = -1-23
3y=-24
Y=-7

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