Question

solve the linear equations by elimination method 2 x minus 7 y is equal to 1 and 4 x + 3 y is equal to 15
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Answer 1

Answer

(56/17, 13/17)

Step-by-step explanation:

$2 x- 7y = 1 \\4x + 3y = 15 \\ - \: \: \: \: \: \: \: \: 4(2 x - 7y = 1) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \:2(4x + 3y = 15) \\ - \: \: \: \: \: \: \: \: \: 8x - 28y = 4 \\ \: \: \: \: \: \: \: \: \: \: \: \: 8x + 6y = 30 \\ = 0 - 34y = - 26$

$\\y = \frac{26}{34} \\y = \frac{13}{17}$

Solve for x

2x - 7y = 1

2x - 7(13/17) = 1

34x - 91/17 = 1

34x - 91 = 17

34x = 17 + 91

34x = 108

x = 108/34

x = 56/17

Verification

2x - 7y = 2

2(56/17) - 7(13/17) = 1

108/17 - 91/17 = 1

17/17 = 1

1 = 1

Answer 2

Answer:

Answer

(56/17, 13/17)

Step-by-step explanation:

\begin{gathered}2 x- 7y = 1 \\4x + 3y = 15 \\ - \: \: \: \: \: \: \: \: 4(2 x - 7y = 1) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \:2(4x + 3y = 15) \\ - \: \: \: \: \: \: \: \: \: 8x - 28y = 4 \\ \: \: \: \: \: \: \: \: \: \: \: \: 8x + 6y = 30 \\ = 0 - 34y = - 26 \end{gathered}2x−7y=14x+3y=15−4(2x−7y=1)2(4x+3y=15)−8x−28y=48x+6y=30=0−34y=−26

\begin{gathered}\\y = \frac{26}{34} \\y = \frac{13}{17} \end{gathered}y=3426y=1713

Solve for x

2x - 7y = 1

2x - 7(13/17) = 1

34x - 91/17 = 1

34x - 91 = 17

34x = 17 + 91

34x = 108

x = 108/34

x = 56/17

Verification

2x - 7y = 2

2(56/17) - 7(13/17) = 1

108/17 - 91/17 = 1

17/17 = 1

1 = 1