Question

solve the linear equations by substituting method

√2x+√3y=0
√3x+√8y=0​

Answer 1

Answer:

y= 0 and x= 0

look down for explanation

Step-by-step explanation:

• (√ 2x )+(√3 y )= 0
• (√3x) - (√8y)= 0
• (√2 x)+(√3y)= 0
• x= - √3 y /√2
• putting in √3 x-√8 y = 0
• √3 (-√3 y/√ 2)-√8 y= 0
• -3 y -4 y = 0
• -7 y = 0

therefore, y=0

x=0

Answer 2

$\huge{ \boxed{ \green{ \sf{Answer:-}}}}$

We have,

√2x + √3y = 0

√3x - √8y = 0

From Equation (1), We deduce:

⇒ √2x = -√3y

⇒ x = -√3y / √2

Plugging in equation (2),

⇒ √3(-√3y/√2) - √8y = 0

⇒ -3y/√2 - 2√2y = 0

Taking y in common,

⇒ y ( -3/√2 - 2√2) = 0

⇒ y = 0

Then,

⇒ x = -√3 × 0 / √2

⇒ x = 0

Hence,

The required value of x and y:

$\huge{ \boxed{ \red{ \sf{0 \:and \: 0}}}}$

Explore more!!

For solving the above, you can also try using the other ways of solving like:

• Graphical method
• Elimination method
• Cross multiplication method.