Question

solve the linear equations using elimination method:- 7(y+3)-2(x+2)=14 4(y-2)+3(x-3)=2​

Answer 1

Answer:

y=1,x=5

Step-by-step explanation:

7(y+3)-2(x+2)=14

=>7y+21-2x-4=14

=>7y+17-2x=14

=>7y-2x=14-17

=>7y-2x=-3 ------1st equation 4(y-2)+3(x-3)=2

=>4y-8+3x-9=2

=>4y+3x-17=2

=>4y+3x=2+17

=>4y+3x=19 ------2nd equation 3[7y-2x=-3]

2[4y+3x=19]

21y-6x=-9 -------3rd equation 8y+6x=38  -------4th equation

by elimination  adding eqation 3 and 4 we get

29y=29 =>y=1

put 'y' is equal to 1 in equation 3 7-2x=-3

-2x=-10

=>x=5