Solve the linear system of equations:
3x + y = 20
x + y = 12
The answer is a ordered pair!
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let 3x + y = 20 be eqn (1)
let x+ y= 12 be eqn (2)
therefore do (1)-(2)
3x+y=20
-×-y=-12
_______
2x=8
x=4
put x =4 in (2)
4+y=12
y=8
let x+ y= 12 be eqn (2)
therefore do (1)-(2)
3x+y=20
-×-y=-12
_______
2x=8
x=4
put x =4 in (2)
4+y=12
y=8
lukehardy:
it needs to be an ordered pair.
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