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The magnitude of addition of two vector is equal to magnitude of subtraction of two vector. Find angle b/w the vector.
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Magnitude of the sum of a and b is √(a²+b²+2(ab)cosX
Difference in their magnitudes is a-b
So,
√(a²+ b²+2(ab)cosX) = a-b
Squaring both sides,
a²+b²+2(ab) cosX = a²+ b²–2(ab)
2(ab)cosX+2(ab) = 0
2(ab)(cosX +1) = 0
Since 2(ab) cannot be zero, cos x+1=0
CosX=-1
X=180
Therefore, the angle between the vectors is 180°.
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