Question

solve the math but no spam please this is my request to all

no. 8 and 10​

Answer 1

Answer:

Step-by-step explanation:

Q.8    BRPQ is a quadrilateral

Thus, By angle sum property <B + <R + <P + <Q = 360°

SO 35 + 90 + <P + 90 = 360

<P = 360 - 215

<P = 145°

Q.10 Let ABCD be a quadrilateral.

Given CO and DO are angle bisectors so <DCO + <CDO = 1/2 (<C+<D)

Now In traingle COD by angle sum property <COD = 180 - (<DCO +<CDO)

 <COD = 180 - ( 1/2 )(<C+ <D)

<COD = 180 - 1/2 {360 - (<A+<B) }

<COD = 180 - 180 + 1/2(<A+<B)

<COD = 1/2 (<A + <B)

2 *<COD = <A+<B  

Hence Proved

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Answer 2

Answer:

8)Quadrilateral has 360 degrees

So here 3 angles given

So 35 + 90 + 90 + x = 360

=> x = 145 degrees