Question

Solve the math equation
Class 8​

Answer 1

HOPE THIS WILL HELP YOU!

Answer 2

Answer:

2. On simplifying ($\frac{2}{3}$ * $\frac{15}{-16}$) - ( $\frac{7}{12}$ * $\frac{-24}{35}$), we get $\frac{-9}{40}$

3. x² + 4x + 11   must be added to 2x² - 3x - 8 to get 3x² + x + 3.

4. On simplifying 3x(2x²-x+1) +2x²(5x+3), we get x( 16x² + 3x + 3)

Step-by-step explanation:

2. ($\frac{2}{3}$ * $\frac{15}{-16}$) - ( $\frac{7}{12}$ * $\frac{-24}{35}$)

This can be written as

=> ($\frac{2}{3}$ * $\frac{3*5}{2*(-8)}$) - ( $\frac{7}{12}$ * $\frac{12*(-2)}{7*5}$)

On simplifying, we get,

=> ( $\frac{5}{-8}$) - ( $\frac{-2}{5}$)

=> -  $\frac{5}{8}$ +  $\frac{2}{5}$

=>    $\frac{2}{5}$ -  $\frac{5}{8}$

Taking LCM,

=> $\frac{2*8 - 5*5}{40}$

=>  $\frac{16 - 25}{40}$

=> $\frac{-9}{40}$

3. Let 'n' be added to 2x² - 3x - 8 to get 3x² + x + 3

=> 2x² - 3x - 8 +n = 3x² + x + 3

=> n = 3x² + x + 3 - (  2x² - 3x - 8 )

=> n =  3x² + x + 3 -  2x² + 3x + 8              because (-)*(-) = (+) and (-)*(+) = (-)

=> n =  x² + 4x + 11  

Therefore, x² + 4x + 11   must be added to 2x² - 3x - 8 to get 3x² + x + 3.

4. We need to simplify 3x(2x²-x+1) +2x²(5x+3)

Opening the brackets, we get,

6x³ - 3x² + 3x + 10x³ + 6x²                

= 16x³ + 3x² + 3x  

Taking x common, we get,

x( 16x² + 3x + 3)

Therefore, on simplifying 3x(2x²-x+1) +2x²(5x+3), we get x( 16x² + 3x + 3)