solve the math question the side of a rectangular Park are in ratio 4 : 3.If its area is 2028 sq. m.Find the cost of fencing it at ruppees 3 per m.
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let the ratio constant be x
so sides are 4x and 3x
area of rectangular park=length*breadth
2028=4x*3x
2028=12x^2
2028/12=x^2
169=x^2
√169=x
13=x
4x=4*13
=52
3x=3*13
=39
perimeter =2(l+b)
=2*(52+39)
=2*91
=182m
fencing=3*182
Rs.526
so sides are 4x and 3x
area of rectangular park=length*breadth
2028=4x*3x
2028=12x^2
2028/12=x^2
169=x^2
√169=x
13=x
4x=4*13
=52
3x=3*13
=39
perimeter =2(l+b)
=2*(52+39)
=2*91
=182m
fencing=3*182
Rs.526
mukesh188:
i do it please do not give me ans.
Answered by
0
let the ratio constant be x
so sides are 4x and 3x
area of rectangular park=length*breadth
2028=4x*3x
2028=12x^2
2028/12=x^2
169=x^2
√169=x
13=x
4x=4*13
=52
3x=3*13
=39
perimeter =2(l+b)
=2*(52+39)
=2*91
=182m
fencing=3*182
=546
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