Question

solve the matrix method
x+2y+3=8
2x+y-3=1
x-y+3=2

Answer 1

Step-by-step explanation:

x-y+3=2

=y=x+1

now y=x+1 on equation 2

2x+y-3=1

2×+x+1-3=1

3x=3

x=1

now x = 1 in equation 1

1+2y+3=8

2y=4

y=2

HENCE X=1,Y=2.

Answer 2

Answer:

27(x+y)

3

+8(2x−y)

3

Above terms can be written as,

3

3

(x+y)

3

+2

3

(2x−y)

3

(3(x+y))

3

+(2(x−y))

3

We know that,a

3

+b

3

=(a+b)(a

2

−ab+b

2

)

Where,a=3(x+y),b=2(x−y)

=[3(x+y)+2(2x−y)][(3(x+y))

3

−(3(x+y)×2(2x−y))+(2(2x−y))

2

]

=[3x+3y+4x−2y][9(x+y)

2

−6(x+y)(2x−y)+4(2x−y)

2

]

=(7x−y)[9(x

2

+y

2

+2xy)−6(2x

2

−xy+2xy−y

2

)+4(4x

2

+y

2

−4xy)]

=(7x−y)[9x

2

+9y

2

+18xy−12x

2

−6xy−6y

2

+16x

2

+4y

2

−16xy]

=(7x−y)[13x

2

−4xy+19y

2

]