Math, asked by reyrazel3715, 1 year ago

solve+the+method+by+substitution+method++:root+2x+root5y+=0+++root6x+root15y=0

Answers

Answered by ShaikJavidbasha
0

Answer:

Step-by-step explanation:

root2x + root5y = root6x + root15y

squairing on both sides

2x + 5y = 6x + 15y

6x - 2x = -15y + 5y

4x = -10y

x/y = -10/4

x/y = -5/2

x = -5y/2

2(-5y/2) + 5y = 0

-5y + 5y = 0

y = 0

x = -5(0) /2 = 0

x = 0

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