solve+the+method+by+substitution+method++:root+2x+root5y+=0+++root6x+root15y=0
Answers
Answered by
0
Answer:
Step-by-step explanation:
root2x + root5y = root6x + root15y
squairing on both sides
2x + 5y = 6x + 15y
6x - 2x = -15y + 5y
4x = -10y
x/y = -10/4
x/y = -5/2
x = -5y/2
2(-5y/2) + 5y = 0
-5y + 5y = 0
y = 0
x = -5(0) /2 = 0
x = 0
Similar questions
History,
6 months ago
Math,
6 months ago
Chemistry,
6 months ago
English,
1 year ago
English,
1 year ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago