Solve the newton s method a root of x^3-3x-5
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To find the roots of the equation x3-3x-5 up to 5 decimal places using the Newton Raphson Method. Follow the steps to solve the questions.
Given equation f(x) = x3 - 3x - 5
Differentiate with respect to x, we get f '(x) = 3x2-3
Now first find the range, where the real roots lie in i.e f(2) = - 3 and f(3) = 13
Since f(2) is a negative value and f(3) is a positive value. Therefore, our one real root of the equation lies between x = 2 and 3.
Now, by Newton's- Raphson formula
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the above figure is the answer of Find the real root of by Newton Raphson method
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