Question

solve the pair 2x+3y=12 and 3x+2y=13 elemination method.​

Answer 1

Answer:

answer is the value of x is 3 and the value of Y is 2 .

Answer 2

Answer:

$\Large\boxed{Y=2, \quad X=3}$

Step-by-step explanation:

GIVEN:

2x+3y=12 and 3x+2y=13 (by using with elimination method formula.)

To solve this problem, first you have to use the elimination method formula from left to right numbers. Isolate by the x or y on one side of the equation.

SOLUTIONS:

First, multiply the numbers from left to right.

$\displaystyle \begin{bmatrix}2x+3y=12\\ 3x+2y=13\end{bmatrix}$

$\displaystyle 12*3=36$

$\displaystyle 13*2=26$

Rewrite the whole problem down.

$\displaystyle \begin{bmatrix}6x+9y=36\\ 6x+4y=26\end{bmatrix}$

Subtract the numbers from left to right.

$\displaystyle 6x+9y=36\quad -\quad 6x+4y=26$

$\displaystyle 9-4=5$

$\displaystyle -5y=-10$

$\displaystyle \begin{bmatrix}6x+9y=36\\ -5y=-10\end{bmatrix}$

Isolate by the y from one side of the equation.

$\displaystyle -5y=-10$

Divide by -5 from both sides.

$\displaystyle \frac{-5}{-5}=\frac{-10}{-5}$

Solve.

Divide the numbers from left to right.

$\displaystyle -10\div-5=\boxed{2}$

$\Large\boxed{Y=2}$

Isolate by the x from one side of the equation.

$\displaystyle 6x+9*2=36$

Multiply.

$\displaystyle 2*9=18$

$\displaystyle 6x+18=36$

Then, you subtract by 18 from both sides.

$\displaystyle 6x+18-18=36-18$

Solve.

Subtract.

$\displaystyle 36-18=18$

$\displaystyle 6x=18$

Divide by 6 from both sides.

$\displaystyle \frac{6x}{6}=\frac{18}{6}$

Solve. (Simplify/ to find the answer!)

Divide.

$\displaystyle 18\div6=\boxed{3}$

$\Large\boxed{X=3}$

$\Large\boxed{Y=2 \quad X=3}$

Hence, the correct answer is y=2 and x=3.