Question

Solve the pair of equation: 43x+67y=-24 and 67x+43y=24

Answer 1

We have,
43x+67y=-24 ---------------------(i)
67x+43y=24 ----------------------(ii)


Multiplying eq.(i)by43 and eq.(ii)by 67 we get

43(43x+67y)=-24×43
1,849x+2,881y=-1,032 ------------------(iii)



67(67x+43y)=24×67
4,489x+2,881y=1,608 ------------------(iv)


Sub.eq (iii) from (iv) we get;




=>4,489x+2,881y -(1,849x+2,881y)=1,608 -(-1,032)
=>4,489x+2,881y -1,849x-2,881y=1,608+1,032
=>2,640x=2,640
=>x=2,640/2640
=>x=1


Putting x=1 in eq.(i) we get;
43(1)+67y=-24
43+67y=-24
67y=-24-43
67y=-67
y=-67/67
y=-1

Answer 2

Hi Guys!!

We have,

43x+67y=-24 ---------------------(i)

67x+43y=24 ----------------------(ii)

Multiplying eq.(i)by43 and eq.(ii)by 67 we get

43(43x+67y)=-24×43

1,849x+2,881y=-1,032 ------------------(iii)

67(67x+43y)=24×67

4,489x+2,881y=1,608 ------------------(iv)

Sub.eq (iii) from (iv) we get;

=>4,489x+2,881y -(1,849x+2,881y)=1,608 -(-1,032)

=>4,489x+2,881y -1,849x-2,881y=1,608+1,032

=>2,640x=2,640

=>x=2,640/2640

=>x=1

Putting x=1 in eq.(i) we get;

43(1)+67y=-24

43+67y=-24

67y=-24-43

67y=-67

y=-67/67

y=-1

HOPE IT HELPS U !!!!!