Question

solve the pair of equation by method of substitution 2x + 3y =10 and 3x -y-4=0

solve fast please ​

Answer 1

Answer:

2

Step-by-step explanation:

2x+3y=10

= y=(10-2x)/3

Substituting the value to the second equation,

= 3x(10-2x)/3=4

= (9x-10+2x)/3=4

= 11x-10=12

= x=22/11=2

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Answer 2

Step-by-step explanation:

2x+3y=10 .

3x-y-4=0

2x+3y=10••••• 1

3x-y-4=0•••••2

3x-4=y•••••• 3

substitute equation 3 in 1

2x+3y=10

2x+3(3x-4)=10

2x+9x-12=10

11x =10+12

11x=22

x=22/11

x=2

substitute X in equation 3

3x-4=y

3(2)-4=y

6-4=y

2=y