Question

Solve the pair of equation by substitution method: 5x + 8y – 18=0 and 2x – 3y – 1 =0

Answer 1

Answer:

solution

by substitution method:-

$here \\ 5x + 8y - 18 = 0............(1) \\ 2x - 3y - 1 = 0................(2) \\ so \\ = > 10x + 16y - 36=0 \\ = > \:10x - 15y - 5=0 \\ = > y = 1 \\ now \: putting \: value \: of \: x(1) \\ = > 5x + 8y - 18 = 0 \\ = > 5x + 8 \times 1 - 18 = 0 \\ = > 5x = 18 - 8 \\ = > x = \frac{ 10}{5} = > 2$

hence X=2 ,Y=1