Question

Solve the pair of equation by the elimination method: x-5=3(y-5);x-2y=10​

Answer 1

Answer:

x- 5= 3(y-5) .....( eqn.1)

Step-by-step explanation:

x -2y=10......(eqn.2) solve ...eqn.1

x-5=3y-15

x-3y=-15+5

x-3y=-10 .....( eqn.1)

now elimination method

( x-3y=-10) × 1

(x-2y=10)×1

x-3y=-10

x-2y=10

y= 20

(x-3y=-10)×-2

(x-2y=10)×-3

-2x+6y=20

-3x+6y=-30

x=50

x=50 and y=20

Answer 2

Solution:-

Take

x - 5 = 3( y - 5 )

x - 5 = 3y - 15

x - 3y = - 15 + 5

x - 3y = - 10 ..........(i)eq

x - 2y = 10 ..........(ii)eq

Using elimination method

Subtract (ii) from ( i )

x - 3y - ( x - 2y ) = -10 - 10

=> x - 3y - x + 2y = - 20

=> - 3y + 2y = - 20

=> -y = - 20

y = 20

Now put the value of y in (ii) eq

x - 2y = 10 ..........(ii)eq

x - 2×(20) = 10

x - 40 = 10

x = 10 + 40

x = 50

Answer

y = 20 and x = 50