Question

solve the pair of equation using substitution method 2x-y=5 ,3x+2y=11

Answer 1

let take x = 3 and y =1

then

1. 2(3)-1=5

6-2=5

5=5

2. 3(3)+2(1)=11

9+2=11

11=11

Answer 2

In the 1 eqn take everything to rhs except y to get x value

So the eqn becomes

Y = 2x-5

Substitute value of y in the eqn 2 get the respective values

So eqn 2 now becomes

3x + 2(2x-5) = 11
3x+4x= 11+10
7x=21
X=3

Now substitute x=3 in any eqn to find value of y

Y=2x-5
Y= 2(3) -5
Y=1