Question

Solve the pair of equations 3x +2y-13= 0 and 6x-4y-10 =0 by
using substitution method.​

Answer 1

Answer:

take the given equation has 1 and 2

from 1, 3x=13-2y and put x=(13-2y)/3----3 in equ 2,

6(13-2y)/3-4y-10=0

2(13-2y)-4y-10=0

26-4y-4y-10=0

16=8y

y=2

put y=2 in equ 3,

x=(13-2(2))/3

x=(13-4)/3

x=9/3

x=3