Question

solve the pair of equations 3x-2y=8 and 5x-10y=10 by elimination method

Answer 1

GIVEN :

Two equations :

3x-2y=8 and 5x-10y=10

3x - 2y = 8 × 5

5x - 10y = 10 × 1

-------------------

15x - 10y = 40

5x - 10y = 10

- (+) -

-------------------

10x = 30

-------------------

x = 30/10

x = 3

Substitute 3 in any equation

5x - 10y = 10

5(3) - 10y = 10

15 - 10y = 10

15 - 10 = 10y

5 = 10y

5 /10 = y

y = 1/2

Therefore, x and y are 3 and 1/2 respectively.

Answer 2

Answer:

$\large \text{x = 3 and y=\dfrac{1}{2} }$

Step-by-step explanation:

Given :

3 x - 2 y = 8

Multiply it by 5 we get

15 x - 10 y = 8 ....( i )

We have other equation

5 x - 10 y = 10 ... ( ii )

Subtracting  ( i )  from  ( ii )  we get

15 x - 10 y = 40

 5 x - 10 y = 10

-      +          -    

10 x = 30

x = 3  

Now putting x = 3 in ( i )

5 x - 10 y = 10

10 y = 5 x - 10

10 y = 15 - 10

10 y =  5

2 y =  1

$\large \text{ y=\dfrac{1}{2} \ Decimal value 0.5}$

$\large \text{Thus we get x = 3 and y=\dfrac{1}{2} }$