Question

solve the pair of equations by reducing them to a pair of linear equations= 3x+2y/xy=1 and 4x-2y/xy= 13. hence find a for which y= ax-4.

Answer 1

(3x+2y)/xy=1

3x + 2y = xy  ----- (i)


(4x-2y)/xy= 13

4x - 2y = 13xy ----- (ii)

Add (i) to (ii)

7x = 14xy

7 = 14y

y = 1/2


3x + 2(1/2) = x(1/2)

3x + 1 = x/2

3x - x/2 = -1

2(1/2)x = -1

x = -2/5 

--------------------------------------------------------------------------

y= ax-4

1/2 = a(-2/5) - 4

4(1/2) = -2a/5

a = -4/45