Solve the pair of equations by reducing them to a pair of linear equations.
(x + y)/xy = 2
(x - y)/xy = 6
Answers
Answered by
1
Hi ,
It is given that ,
( x + y )/xy = 2
=> x/xy + y/xy = 2
=>1/y + 1/x = 2 ----( 1 )
( x - y )/xy = 6
=>x/xy - y/xy = 6
=> 1/y - 1/x = 6 ----( 2 )
add equations ( 1 ) and ( 2 ) , we get
2/y = 8
2/8 = y
1/4 = y
y = 1/4
substitute y = 1/4 in equation ( 1 ) ,
we get
1/4 + 1/x = 2
1/x = 2 - 1/4
1/x = ( 8 - 1 )/4
1/x = 7/4
x = 4/7
I hope this helps you.
: )
It is given that ,
( x + y )/xy = 2
=> x/xy + y/xy = 2
=>1/y + 1/x = 2 ----( 1 )
( x - y )/xy = 6
=>x/xy - y/xy = 6
=> 1/y - 1/x = 6 ----( 2 )
add equations ( 1 ) and ( 2 ) , we get
2/y = 8
2/8 = y
1/4 = y
y = 1/4
substitute y = 1/4 in equation ( 1 ) ,
we get
1/4 + 1/x = 2
1/x = 2 - 1/4
1/x = ( 8 - 1 )/4
1/x = 7/4
x = 4/7
I hope this helps you.
: )
rohitkumargupta:
please correct it
Answered by
1
HELLO DEAR,
(x + y)/xy = 2
x + y = 2xy-----------( 1 )
(x - y)/xy = 6
x - y = 6xy ----------( 2 )
from-----( 1 ) & ------( 2 )
x + y = 2xy
x - y = 6xy
-----------------
2x = 8xy
y = 1/4 [ put in ---( 1 )]
x + y = 2xy
x + 1/4 = 2x(1/4)
x + 1/4 = x/2
1/4 = (x - 2x)/2
-x = 1/2
x = -1/2 , y = 1/4
I HOPE ITS HELP YOU DEAR,
THANKS
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