Question

Solve the pair of equations in x and y graphically x+y-1=0,x-y+1=0​

Answer 1

Step-by-step explanation:

For equation x–y+1=0 or x=y−1, we have following points which lie on the line

Plug y=0,1 we get

x=0−1=−1

x=1−1=0

Therefore, the required points are (−1,0),(0,1).

For equation 3x+2y–12=0 or y=

2

12−3x

, we have following points which lie on the linePlug x=0,4 we get

y=

2

12−0

=6

y=

2

12−12

=0

Therefore, the required points are (0,6),(4,0).

We can see from the graphs that points of intersection of the lines with the x–axis are (–1,0),(2,3) and (4,0).