Math, asked by ushaushu75, 3 months ago

Solve the pair of linear equation
2x+ y = 10 and x - y = 12.​

Answers

Answered by omkarbaviskar2302
2

Answer:

x = 22/3, y = -14/3

Step-by-step explanation:

2x + y = 10 and x - y = 12.

Adding both the equations

3x = 22

x = 22/3

as,

x - y = 12

y = x - 12

y = (22/3)-12

y = -14/3

Hope this answer helped you

Answered by CuteAnswerer
14

GIVEN :

  • \bf{2x +y = 10} and \bf{x-y = 12}

TO DO :

  • Solve the pair of linear equations.

SOLUTION :

Adding both equations :

 \implies \sf(2x + y) + (x - y) = 10 + 12 \\ \\

\implies \sf2x + y + x - y = 22 \\ \\

\implies \sf2x + x + \cancel{y} - \cancel{y }= 22 \\ \\

\implies \sf2x + x = 22\\ \\

\implies \sf 3x =22 \\ \\

\implies  {\underline{\boxed{ \blue{\bf {x = \dfrac{22}{3} }}}}}

Substituting the obtained value of x in the first equation :

\implies \sf {2 \times  \dfrac{22}{3}  +y = 10}\\ \\

\implies \sf  \dfrac{44}{3}  + y = 10 \\ \\

\implies \sf y = 10 -  \dfrac{44}{3}  \\ \\

\implies \sf y = \dfrac{30 - 44}{3}\\ \\

\implies{\underline{\boxed{ \red{ \bf {y =  \dfrac{-14}{3} }}}}}

\huge{\green{\therefore}} The value of x and y is \bf{\dfrac{22}{3}} and \bf{\dfrac{-14}{3}} respectively.

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