Question

solve the pair of linear equation 2x-y=2 and 4x-y=4​

Answer 1

Step-by-step explanation:

2x−y=2 ----- (1)

−4x−y=−4 ----- (2)

From equation (1)

y=2x−2 ------ (3)

Assume the value of x = 1, 2 and put those values in equation (3)

If x=1,y=2(1)−2=0

If x=2,y=2(2)−2=2

On the above basis, the following points are:

X 1 2

Y 0 2

Now plotting (1, 0), (2, 2) and joining them, we get a straight line.

From equation (2),

−4x−y=−4

y=−4x+4 ------ (4)

Assume the value of x=1,2 and put those values in equation (3)

If x=1,y=−4(1)+4=0

If x=2,y=−4(1)+4=−2

Now table the following points:

X 1 2

Y 0 -2

Plotting (1, 0), (2, -2) and joining them, we get another straight line.

These lines intersect at the point (1, 0) and therefore the solution of the equation is x=1,y=0

Answer 2

Answer:

Given:-

2x-y=2-----(I)

4x-y=8-----(II)

Solution:-

Subtracting the polynomial (I) & (ii)

Subtracting the polynomial (I) & (ii)2x-y=2-----(I)

Subtracting the polynomial (I) & (ii)2x-y=2-----(I)4x-y=8-----(ii)

Subtracting the polynomial (I) & (ii)2x-y=2-----(I)4x-y=8-----(ii)(-) (+) (-)

Subtracting the polynomial (I) & (ii)2x-y=2-----(I)4x-y=8-----(ii)(-) (+) (-)________

Subtracting the polynomial (I) & (ii)2x-y=2-----(I)4x-y=8-----(ii)(-) (+) (-)________-2x=-6

Subtracting the polynomial (I) & (ii)2x-y=2-----(I)4x-y=8-----(ii)(-) (+) (-)________-2x=-6x=-6/-2

Subtracting the polynomial (I) & (ii)2x-y=2-----(I)4x-y=8-----(ii)(-) (+) (-)________-2x=-6x=-6/-2=>x=3

Substituting value of x=3 in equation(I)

2×3-y=2

6-y=2

y=6-2

y=4

Therefore the answer is (x,y)=(3,4)

Step-by-step explanation:

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