solve the pair of linear equation 3x+y=-1 and -2x+3y=19 and find m so that y=mx+3 by substitution method only
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Step-by-step explanation:
[-(3x+y) =-1] ×3~ equation 1 -2x+3y=19~ equation 2
add both
-9x-3y=+3
-2x+3y=19
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-11y= 22
therefore y=(-2)
putting y=(-2) in equation 2
-2x+3(-2)=19
-2x-6=19
-2x= 24
x= -12
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