Question

solve the pair of linear equation by cross multiplication method:5x+8y-18=0 and 2x-3y-1=0​

Answer 1

this is the answer wt I got I am sure that this is the correct answer trust me my steps are proper and I rechecked it

Answer 2

Answer:

The pair for the given linear equations is (2,1)

Step-by-step explanation:

Given equations are 5x+8y-18=0 and 2x-3y-1=0​

To find the pair of linear equation by cross multiplication method :

5x+8y-18=0

2x-3y-1=0​

By using the cross multiplication method we can write the given equations as

8     -18       5      8

-3      -1        2      -3

__________________

$\frac{x}{8(-1)-(-3)(-18)}=\frac{y}{(-18)(2)-(-1)(5)}=\frac{1}{5(-3)-(2)(8)}$

$\frac{x}{-8-54}=\frac{y}{-36+5}=\frac{1}{-15-16}$

$\frac{x}{-62}=\frac{y}{-31}=\frac{1}{-31}$

Now equating $\frac{x}{-62}=\frac{1}{-31}$

$\frac{x}{62}=\frac{1}{31}$

$x=\frac{62}{31}$

Therefore x=2

Now equating $\frac{y}{-31}=\frac{1}{-31}$

$\frac{y}{31}=\frac{1}{31}$

$y=\frac{31}{31}$

Therefore y=1

The pair for the given linear equations is (2,1)

The solution is (2,1)