Solve the pair of linear equation by elimination and substitution method
X+y= 5 and 2x-3y= 4
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Answer:
by elimination method
2x+2y=10 (multiply by 2)
-2x+3y=4
0-y=6
y= -6
x=5-y=5-(-6)
=5+6=11
by substitution method
let y=5-x. eqn 1
put the value of the eqn 1 in
2x+3y=4
2x+3*5-x=4
2x+15-3x=4
-x+15=4
x=15-4=11
y=5-x
=5-11= -6
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