Solve the pair of linear equation by elimination method.
1/3x+1/2y=3,
1/5x+3/5y=3
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3
Step-by-step explanation:
Solved this equation by elimination method. Now you can check the answer by putting the value of x in the equation and LHS=RHS.
HOPE YOU UNDERSTAND
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Answered by
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Step-by-step explanation:
1/3x+1/2y=3
2x+3y/6=3
2x+3y=3x6
2x+3y=18_______(I)
1/5x+3/5y=3
5x+15y/5=3
5x+15y=15________(ii)
by multiplying eq(I) by 5 we get
5(2x+3y)=18x5
10x+15y=90
by subtracting (I) and (ii)
10x+15y-(5x+15y)=90-15
10x+15y-5x-15y=75
5x=75
y=15
by putting the value of y in (I)
2x+3x15=18
2x+45=18
2x=18-45
2x=27
X=27/2
I don't know it is correct or not but I tried to solve it I hope this will help you
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