Question

solve the pair of linear equation by elimination method​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore (1)x=1\:and\:y=2}}$

${\bold{\therefore (2)x=3\:and\:y=4}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\bold{For \: first \: question : } \\ \\ \underline \bold{Given : }\\ \implies 2x + 3y = 8 \\ \\ \implies x + 2y = 5 \\ \\ \underline \bold{To \: Find : } \\ \implies x = ? \\ \\ \implies y= ? \\ \\ \bold{Using \: elimination \: method : } \\ \implies 2x + 3y = 8 - - - - - (1) \\ \\ \implies x + 2y = 5 - - - - - (2) \\ \\ \bold{multiplying \: 2 \: in \: (2)} \\ \implies 2x + 4y = 10 - - - - - (3) \\ \\ \bold{subtracting \: (3) \: from \: (1)} \\ \implies 2x + 3y - 2x - 4y = 8 - 10 \\ \\ \implies - y = - 2 \\ \\ \bold{\implies y = 2} \\ \\ \bold{putting \: value \: of \: y \: in \: (1)} \\ \implies 2x + 3y = 8 \\ \\ \implies 2x + 3 \times 2 = 8 \\ \\ \implies 2x = 8 - 6 \\ \\ \implies x = \frac{2}{2} \\ \\ \bold{\implies x = 1}$

$\bold{For \: second\: question : } \\ \\ \underline \bold{Given : }\\ \implies 3x + 4y = 25 \\ \\ \implies 5x - 6y = - 9\\ \\ \underline \bold{To \: find : } \\ \implies x = ? \\ \\ \implies y= ? \\ \\ \bold{using \: elimination \: method : } \\ \implies 3x + 4y = 25 - - - - - (1) \\ \\ \implies 5x - 6y = - 9- - - - - (2) \\ \\ \bold{multiplying \: 5\: in \: (1) \: and \: 3 \:in \: (2)} \\ \implies 15x + 20y =125 - - - - - (3) \\ \\ \implies 15x - 18y = - 27 - - - - - (4)\\ \\ \bold{subtracting \:(4) \: from \: (3)} \\ \implies 15x + 20y - 15x + 18y= 125 - ( - 27)\\ \\ \implies 38y = 152 \\ \\ \implies y = \frac{\cancel{152}}{\cancel{38}} \\ \\ \bold{\implies y = 4} \\ \\ \bold{putting \: value \: of \: y \: in \: (1)} \\ \implies 3x + 4y = 25\\ \\ \implies 3x + 4\times 4 = 25\\ \\ \implies 3x = 25 - 16\\ \\ \implies x = \frac{\cancel9}{\cancel3} \\ \\ \bold{\implies x =3}$

Answer 2

Answer:

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