Question

solve the pair of linear equation by elimination method 7s-9t=3. 14s-9t​

Answer 1

Answer:

7s-9t=3......i

14s-9t=0.......ii

By elimination method.

Subtract EQ 1 from eq2

14s-9t=0

-7s+9t=-3. Add

----------------

7s=-3

!S=-3/7!

.....…......

put value of s in eq1

7s-9t=3

7(-3/7)-9t=3

-9t=3+3

-9t=6

t=6/9

!t=2/3!

............

So this is you answer

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