Question

Solve the pair of linear equation by elimination method x+2y = 2 and x-3y = 7

Answer 1

EXPLANATION.

• GIVEN

pair of linear equation by elimination method.

TO FIND X AND Y.

=> x + 2y = 2 ......(1)

=> x - 3y = 7 ........(2)

From equation (1) and (2) we get,

=> multiply equation (1) by 3

=> multiply equation (2) by 2

we get,

=> 3x + 6y = 6

=> 2x - 6y = 14

we get,

=> 5x = 20

=> x = 4

put the value of x = 4 in equation (1)

we get,

=> x + 2y = 2

=> 4 + 2y = 2

=> 2y = 2 - 4

=> 2y = -2

=> y = -1

Therefore,

value of x = 4 and y = -1

Answer 2

Given :

• 2 Equations

• $\sf{x + 2y = 2 \: \: \: \: \: ...(i)}$
• $\sf{x - 3y = 7 \: \: \: \: \: ...(ii)}$

To Find :

• Value Of x and y by Elimination Method.

SOLUTION :

Subtract Equation (2) from (1)

We Get,

$\sf{y = - 1}$

Putting ( y = -1 ) in Equation ( 1 )

$\sf{x + 2( - 1) = 2}$

$\sf{x = 4}$

$\rm \underline{ \blue{ \boxed{ \bf \green{Verification:}}}}$

$\sf{x + 2y = 4}$

$\sf{4 + 2( - 1) = 2}$

$\sf{4 - 2 = 2}$

$\sf{2 = 2}$

$\checkmark \rm \underline{ \blue{ \boxed{ \bf \purple {Verified}}}}$

$\bigstar \small \underline{ \blue{ \boxed{ \bf \blue{x=4,y=-1}}}} \bigstar$