solve the pair of linear equation by substitution method 4x-y=4 and 4x+y=12
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given equation (1)=4x-y=4
given equation (2)=4x+y=12
- now by substitutions method ,
we get,
from (1),
4x=4+y
x=4+y/4............... let this be equation (3)
now,from equation (2),
substitute the equation,i.e x value in (2)
we get,
= 4(4+y/4)+y=12
now, 4+y+y=12
=. 4+2y=12
2y=12-4
2y=8
y=8/2
.
. . y=4,
and now substitute y value in x
we get,. x=4+4/4
x=8/4
=. x=2
so now x=2and y=4
hope you understood this☺️☺️
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Answer:
The Answer is x = 2 , y = 4
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