Question

solve the pair of linear equation by substitution.method

a–b=3 ,a/3+b/2=6



please solve the problem fast and give me the correct solution it's really very important​

Answer 1

Answer:

as given, a-b=3 =>a=b+3 ------>eq(1) ;

also given a/3+b/2=6 => from eq(1) we get

(b+3)/3+b/2=6;

=>(2b+6+b)/6=6

=>3b+6 = 36

=>3b = 30.

we get => b=10

sub b=10 in eq1 we get

a=13

hence a=13 and b=10