solve the pair of linear equation by the substitution and cross multiplication methods
3x+3y=18,
2x-3y=-3
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Answered by
2
3x+3y=18 1
2x -3y=-3 2
Adding both equation'
5x=15
x=3
put x=3 in eqn 1
3x3+3y=18
9+3y=18
3y=18-9
y=9/3
y=3
x=3 & y=3
2x -3y=-3 2
Adding both equation'
5x=15
x=3
put x=3 in eqn 1
3x3+3y=18
9+3y=18
3y=18-9
y=9/3
y=3
x=3 & y=3
debosmita2:
hey thnks
Answered by
1
Here is your answer....
3x+3y=18
2x-3y=-3
__________
5x=15
=x=15/5
=x=3
putting the value of x in first equation..
3x+3y=18
=>3×3+3y=18
=>9+3y=18
=>3y=18-9
=>3y=9
=>y=9/3
=>y=3
Hence x=3. and y=3
3x+3y=18
2x-3y=-3
__________
5x=15
=x=15/5
=x=3
putting the value of x in first equation..
3x+3y=18
=>3×3+3y=18
=>9+3y=18
=>3y=18-9
=>3y=9
=>y=9/3
=>y=3
Hence x=3. and y=3
thnx
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