Question

solve the pair of linear equation=px+qy=p and qx-py=p+q

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Answer 1

Answer:

here x=pq and y=p(1-p)

Step-by-step explanation:

let px+qy=p______eqn. 1

qx-py=p+q_______eqn.2

multiple p with 1 and q with 2

then the equations becomes

p^2x+pqy=p^2 (eqn.3)

q^2-pqy=pq+q^2 (eqn.4)

add both the equations....

p^2x+q^2x=p^2+pq+q^2

x(p^2+q^2)= pq+(p^2+q^2)

cancel the commons

it gives x=pq

then we can put the value of x in eqn.1

after simplification we get

y=p-p(pq)/q

y= p-p^2q/q

cancel q from numerator and denominator

we get y=p-p^2

which can be written as

y=p(1-p)

HOPE IT WILL BE HELPFUL.