Math, asked by mohitkumar84107, 9 months ago

solve the pair of linear equation :x+3y=6,2x-3y=12

Answers

Answered by aarushighosh111
0

Answer:

x = 6 and y = 0

Step-by-step explanation:

x + 3y = 6, 2x - 3y = 12

By Substitution method:

x + 3y = 6

>> x = 6 - 3y

Substuting value of x in 2x - 3y = 12:

2(6 - 3y) - 3y = 12

>> 12 - 6y - 3y = 12

>> -9y = 12 -12 = 1

>> y = 0

Replacing value of y in x + 3y =6:

x + 3*0 = 6

x = 6

Therefore, x = 6 and y =0

Answered by ravinder268
0

Answer:

                        x+3y=6

                      2x--3y=12

                ............................

                       3x=18

                        x=6

substitute in any equation u get y=0

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