solve the pair of linear equation x/6+y/15=4 & x/3-y/12=19/4
Answers
Step-by-step explanation:
x/6 + y/15 =4.
x/3 - y/12 =19/4.
Multiply equation (x/6 + y/15 = 4) by 30 both Left hand side and right hand side.
Now if you multiply Left hand side by 30 we get
30*(x/6 + y/15)
= 30*x/6 + 30*y/15
=5x + 2y.
Now if we multiply Right hand side of the equation by 30 we get
4*30 = 120.
Now if we multiply Left hand side of the equation x/3 - y/12 =19/4 by 12 we get
12*(x/3-y/12)
=12*x/3-12*y/12
=4x-y.
Now if we multiply Right hand side of the equation by 12 we get
12*(19/4)
=3*19
=57.
Now we got two new equations 5x+2y =120 and 4x-y = 57
Now multiply the equation 4x-y = 57 by 2 Both Left hand side and Right hand side we get 2*(4x-y) = 2*57.
We get 8x-2y = 114.
Now if we add 5x + 2y = 120 and 8x-2y = 114 both Left hand side and Right hand side we get
5x+2y+8x-2y = 120 + 114
13x =234
So x = 234/13 = 18.
So if we substitute x= 18 in 5x+2y = 120
We get
5*18 +2y = 120
90 + 2y = 120
2y= 120-90
2y = 30
y = 15.
So x= 18 and y = 15.
Hope you understood.