· Solve the pair of linear equation x - y = 28 and r - 3y = 0. Find such m so that y=mx-28
std 10
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x - 3y = 0
x = 3y (1)
x - y = 28 (2)
Putting the value of x in equation (2) we get
3y - y = 28
2y = 28
y = 14
x = 3y or 42
y = mx - 28
14 = m42 - 28
42 = m42
m = 1
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