Question

Solve the pair of linear equations 2 + 3 = 11 , 2 − 4 = −24 by

Elimination method​

Answer 1

$\small\sf\underline{\green{Answer:-}}$

$\small\bf\underline{\bold{Given\:Equations\:are:-}}$

$2x+3y=11−−−−(1)$

$2x−4y=−24−−−−(2)$

Form:- (1)

$2x+3y=11$

$⇒2x=11−3y$

$⇒x=$

$2$

$11−3y$

−−−(3)

$\small\star\;{\underline{\underline{\bf{\pink{\;substituting\; x \;in :-}}}}}$

$\small{\red{2x−4y=−24 }}$

$\small{\red{⇒2( }}$

$2$

$\small{\red{11−3y}}$

$\small{\red{)−4y=−24}}$

$\small{\red{⇒11−3y−4y=−24}}$

$\small{\red{⇒11−7y=−24}}$

$\small{\red{⇒7y=35}}$

$\small{\red{⇒y=35/7}}$

$\small{\red{⇒y=5.}}$

$\small{\red{putting\: y \:= 5\: in\: (3) }}$

$\small{\red{x= 2}}$

$11−3(5)$

⇒x=

2

11−15

⇒x=−4/2

∴x=−2.

Hence x = -2 and y = 5 is the solution of the

equation.

Now, we have to find m

y=mx+3 ∴m=−1

5=3(−2)+3

5−3=−2m⇒−2m=2

⇒m=−2/x=−1