Question

solve the pair of linear equations 2x+ y-11=0 , x-y -1 =0​

Answer 1

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Answer 2

Answer:

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Step-by-step explanation:

2x+ y-11=0 ------(1)

x-y -1 =0 ---------(2)

Using substitution method

2x +y -11 =0

$x = \frac{11 - y}{2}$

we got the value of x

substitute x value in eq (2) we get

x-y-1 =0

$\frac{11 - y}{2} - y - 1 = 0 \\ \frac{11 - y - 2y - 2}{2} = 0 \\ \frac{ - 3y + 9}{2} = 0$

send 2 to rhs we get

$- 3y + 9 = 0 \\ - 3y = - 9 \\ y = \frac{ - 9}{ - 3} \\ y = 3$

we got the value of y now substitute the value of y in eq 2 we get

x-y -1 =0

=> x -3 - 1 = 0

=>x -4 =0

=> x =4

x =4 ,y = 3

(x,y) = (4,3)