Question

Solve the pair of linear equations: 3x + 2y – 11 = 0, 2x – 3y + 10 = 0 , by Substitution Or Elimination.​

Answer 1

Answer:

by substitution method :-

the value of :-

➡️ x = 1 and

➡️ y = 4 .

for more information, refer to the attachment.

Step-by-step explanation:

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Answer 2

Answer:

3x+2y-11 =0 (eq 1) multiply by 2

we get 6x+4y-22=0. (let eq no 2)

2x-3y+10=0. (eq3 ) multiply by 3

we get 6x-9y+30=0. (let eq no 4)

by elimination method ( eq 2 and and eq 4)

6x+4y-22

6x-9y+ 30

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- +. - ( change the sign )

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0x+13y-52=0

13y-52=0

13y=52

y=52/13

y =4

put the value of y in eq no 1 to get the value of x

3x+2y-11=0. ( y=4)

3x+2(4)-11=0

3x+8-11=0

3x-3=0

3x=3

X=3/3

X =1

to justify the value of X and Y

let us take eq 3

2x-3y+10=0. (X=1). (y=4)

2(1)-3(4)+10=0

2-12+10=0

-10+10=0

0=0