Solve the pair of linear equations : 3x + y =10 and 2x - 3y = 3
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Answer:
3x+y=10--------(1). 2x-3y=3------(2)
y=10-3x --------(3)
substituting eq 3 in 2
2x-3y=3
2x-3[10-3x]=3
2x-30+9x=3
11x=33.
x=33/11
x=3
substituting x value in eq 3
y=10-3x
y=10-3(3).
y=10-9
y=1
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