Question

Solve the pair of linear equations by elimination method: 5x + 3y = 35 and 2x + 4y = 28​

Answer 1

5x + 3y = 35 2x + 4y = 28

[5x + 3y = 35] ×2 [2x + 4y = 28] ×5

10x + 6y = 70 10x + 20y = 140

10x + 20y - (10x + 6y) = 140 - 70

10x + 20y - 10x - 6y = 70

14y = 70

y = 5

5x + 3*5 = 35

5x = 35 - 15

5x = 20

x = 4

Answer 2

Step-by-step explanation:

5x + 3y = 35 ----(1)

2x + 4y = 28 ----(2)

make any one variable same

like..

( 5x + 3y = 35) × 2

=> 10x+6y=70 ------(3)

(2x + 4y = 28) × 5

=> 10x +20y = 140 ------(4)

so eliminating these eq 3 from eq 4

10x +20y = 140

-(10x+6y=70)

-. -. -

____________

0x + 14y= 70

y= 5

putting value of y in eq 1

5x+ (3×5)=35

5x= 35-15

5x= 20

x = 4