Question

Solve the pair of linear equations by the substitution method
s-t=3
s/3+t/2=6

Answer 1

Answer:

Hi there!

s-t =3 -----(1)

s/3 + t/2 = 6 ----(2)

Therefore the first equation is easy, so we convert it into this form:-

s-t = 3

s = 3 +t -----(3)

Now substituting equation (3) in (2)

3+t /3 + t/2 =6

Now we take the LCM of their denominators..except for the RHS..

2×{3+t/3} + 3×{t/2} = 6

6+2t+3t the whole divided by 6 = 6

6+2t+3t = 6×6

2t+3t = 36

5t = 36-6=30

t = 30/5

t =6 -----(4)

Now substitute (4) in (3)

s = 3+6

s = 9

Hope it helps you..

Thank you.